В PHP код нужно внедрить HTML блок, т.е див, который содержит разделитель для галереи (см. скрин).
//html output ob_start(); ?><div id="<?php echo $selector; ?>" class="fg-panel" > <?php foreach($albums as $album) : $thumbnail = ''; if($album->thumbnail && $options['album_selection'] == 'thumbnails') { $thumbnail = plugins_url('/admin/timthumb.php', __FILE__).'?src='.urlencode($album->thumbnail).'&w='.$thumbnails_selection_width.'&h='.$thumbnails_selection_height.'&zc=1&q=100'; } ?> <div class="<?php echo stripslashes($album->title); ?>" data-thumbnail="<?php echo $thumbnail; ?>"><?php $album_files = $this->wpdb->get_results("SELECT * FROM {$this->images_table_name} WHERE album_id='$album->ID' ORDER BY sort ASC"); if($album->description) { echo '<div>'.stripslashes(htmlspecialchars_decode($album->description)).'</div>'; } foreach($album_files as $album_file) { echo $this->get_media_link($album_file->file, $album_file->thumbnail, $options['thumbnail_width'], $options['thumbnail_height'], $options['thumbnail_zc'], $album_file->title, $album_file->description); } ?></div><?php endforeach; ?></div><div class="clearfix_new"></div> <?php
Для примера название дива <div class="clearfix"></div>